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The random variable \(X\) represents the number of defective items in a batch of 7, with the probability distribution given below:
\(x\)
0
1
2
3
4
5
6
7
\(P(X = x)\)
0.4
0.25
0.15
0.1
0.05
0.03
0.02
0.01
Find the probability that there is at least one defective item in the batch.
The probability is
\(\pi\)
\(e\)
\(x\)
\(n\)
\(u_n\)
\(f\)
\(i\)
\(\frac{a}{b}\)
\(\sqrt{\,}\)
\({a}^{b}\)
\(\ln{\,}\)
\(\log{\,}\)
!
\(C\)
7
8
9
←
→
\(\sin{\,}\)
4
5
6
(
)
\(\cos{\,}\)
1
2
3
\(\times\)
\(\div\)
\(\tan{\,}\)
C
0
.
+
-
=
.
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