$$\begin{aligned}\text{Drawn length} &= \frac{\text{Actual length}}{\text{Scale factor}}\\
&= \frac{6\,\mathrm{m}}{200}\\
&= \frac{600\,\mathrm{cm}}{200} &&(\text{unit conversion})\\
&= 3\,\mathrm{cm}\end{aligned}$$So, \(6\,\mathrm{m}\) of actual length represents \(3\,\mathrm{cm}\) of drawn length.