If 4 tickets cost \(\dollar\)28, how much do 6 tickets cost if each ticket costs the same?
- Method 1: Using the Coefficient of Proportionality
Find the unit price (price for 1 ticket):$$\text{Unit price} = \dfrac{28}{4} = 7$$Now multiply by 6 for 6 tickets:$$\text{Total for 6 tickets} = 7 \times 6 = 42$$ - Method 2: Proportion Equation$$\begin{aligned}\dfrac{\textcolor{colorprop}{28}}{\textcolor{colordef}{4}} &= \dfrac{\textcolor{colorprop}{x}}{\textcolor{colordef}{6}} \\
\textcolor{colordef}{4} \times \textcolor{colorprop}{x} &= \textcolor{colorprop}{28} \times \textcolor{colordef}{6} && \text{(cross multiplication)} \\
\textcolor{colorprop}{x} &= \dfrac{\textcolor{colorprop}{28} \times \textcolor{colordef}{6}}{\textcolor{colordef}{4}} \\
\textcolor{colorprop}{x} &= \textcolor{colorprop}{42}\end{aligned}$$
- Method 3: Unit Rate with Equivalent Ratios

- Method 4: Product in Cross

So, \(\textcolor{colordef}{6}\) tickets cost \(\textcolor{colorprop}{42}\) dollars.