\( \definecolor{colordef}{RGB}{249,49,84} \definecolor{colorprop}{RGB}{18,102,241} \)

Sequences

Numerical Sequence

Definition Numerical Sequence
A numerical sequence is an ordered list of numbers \((u_0,\,u_1,\,u_2,\dots)\) defined by a rule.
\(n\) 0 1 2 \(\dots\)
\(u_n\) \(u_0\) \(u_1\) \(u_2\) \(\dots\)
The number \(u_n\) is called the \(n\)th term of the sequence.
Example
What is \(u_4\) of this sequence?
\(n\) 0 1 2 3 4 5 \(\dots\)
\(u_n\) 3 5 7 9 11 13 \(\dots\)

\(u_4 = 11\).

Definition Using a Recursive Rule


Let’s consider a sequence where the first term is \(2\), and each term is obtained by adding \(3\) to the previous term. The terms are:
We observe:
  • \(5 = 2\textcolor{colordef}{+3} \longrightarrow u_1 = u_0\textcolor{colordef}{+3} \longrightarrow u_{0+1} = u_0+3\)
  • \(8 = 5\textcolor{colordef}{+3} \longrightarrow u_2 = u_1\textcolor{colordef}{+3} \longrightarrow u_{1+1} = u_1+3\)
  • \(11 = 8\textcolor{colordef}{+3} \longrightarrow u_3 = u_2\textcolor{colordef}{+3} \longrightarrow u_{2+1} = u_2+3\)
  • \(\vdots\)
  • So the rule is \(u_{n+1} = u_n + 3\)

Definition Recursive Rule
A sequence can be defined by:
  • the first term (starting number): \(u_0\)
  • a recursive rule that tells how to obtain each term from the previous one:
    \(u_{n+1}=\) expression in \(u_n\)
Example
Write the recursive rule when each term is obtained by adding \(2\) to the previous term.

$$u_{n+1}=u_n+2$$

Definition Using an Explicit Rule

Definition Explicit Rule
A sequence can also be defined by an explicit rule (or explicit formula), which gives a direct formula for the \(n\)th term in terms of \(n\):$$u_n = \text{expression in } n$$
Example
Consider the sequence defined by the explicit formula: \(u_n = 3n + 2\).
Write the first five terms of this sequence.

  • For \(n=0\): $$ \begin{aligned}[t] u_0 &= 3 \times 0 + 2 \\ &= 0 + 2 \\ &= 2 \end{aligned} $$
  • For \(n=1\): $$ \begin{aligned}[t] u_1 &= 3 \times 1 + 2 \\ &= 3 + 2 \\ &= 5 \end{aligned} $$
  • For \(n=2\): $$ \begin{aligned}[t] u_2 &= 3 \times 2 + 2 \\ &= 6 + 2 \\ &= 8 \end{aligned} $$
  • For \(n=3\): $$ \begin{aligned}[t] u_3 &= 3 \times 3 + 2 \\ &= 9 + 2 \\ &= 11 \end{aligned} $$
  • For \(n=4\): $$ \begin{aligned}[t] u_4 &= 3 \times 4 + 2 \\ &= 12 + 2 \\ &= 14 \end{aligned} $$
So the first five terms are: \(2,\ 5,\ 8,\ 11,\ 14\).