\( \definecolor{colordef}{RGB}{249,49,84} \definecolor{colorprop}{RGB}{18,102,241} \)
Courses
About
Login
Register
Consider the quadratic equation \(2x^2 - 4x + 2 = 0\).
Find the discriminant.
\(\Delta =\)
7
8
9
+
4
5
6
-
1
2
3
*
C
0
.
÷
Hence, state the nature of the roots of the equation.
As \(\Delta = 0\), there are 2 distinct roots.
As \(\Delta = 0\), there are no real roots.
As \(\Delta = 0\), there is 1 double root.
The solution of the equation is
\(\pi\)
\(e\)
\(x\)
\(n\)
\(u_n\)
\(f\)
\(\frac{a}{b}\)
\(\sqrt{\,}\)
\({a}^{b}\)
\(\ln{\,}\)
\(\log{\,}\)
!
7
8
9
←
→
\(\sin{\,}\)
4
5
6
(
)
\(\cos{\,}\)
1
2
3
\(\times\)
\(\div\)
\(\tan{\,}\)
C
0
.
+
-
=
.
Exit